From: Josh Cheek <josh.cheek@...>
Date: 2010-06-12T15:23:15+09:00
Subject: Re: How can I call foo in Bar.foo ?

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On Sat, Jun 12, 2010 at 12:33 AM, Ntys Dd <ntysdd@gmail.com> wrote:

> it's like this
> .........................
> module Bar
>  def foo
>    puts 'hello'
>  end
>  def bye
>    puts 'bye'
>  end
> end
>
> def Bar.foo
>  #Do something
>  #I want to call foo now
>  #And call bye
>  #...
> end
> .........................
>
> is there anything i can to to solve the problem
> --
> Posted via http://www.ruby-forum.com/.
>
>

I won't advocate this as a solution, but it does seem to meet your
criterion.


module Bar
 def foo
   puts 'hello'
 end
 def bye
   puts 'bye'
 end
end



# Extends Bar's singleton class with its own instance methods
p (class << Bar ; self ; end).ancestors
Bar.extend Bar
p (class << Bar ; self ; end).ancestors


# since Bar is now an ancestor of itself, we can call super from within
class methods
def Bar.foo
  puts "doing something"
  super
  bye
end

Bar.foo

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