From: botp <botpena@...>
Date: 2010-06-04T22:03:38+09:00
Subject: Re: Unexpected length of £ (pound) character?

On Fri, Jun 4, 2010 at 6:47 PM, Brian Candler <b.candler@pobox.com> wrote:
> If you want to capture (say) the first 6 characters of the string, try
>>> a = "1234£6789"
> => "1234\302\2436789"
>>> a =~ /\A(.{6})/u
> => 0
>>> puts $1
> 1234£6
> => nil

>"1234£6789"[0..5]
 => "1234£6"

> ruby 1.9 works in characters. It brings with it enormous complexity,
> pitfalls and inconsistencies. Pick your poison :-)

All programmers are optimists.  -Frederick Brooks, Jr.

;-)

kind regards -botp