From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2010-04-05T23:45:50+09:00
Subject: Re: When {integer:0} <> 0 ???

On Mon, Apr 5, 2010 at 4:35 PM, Richard Fairbanks <lists@f-p-i.com> wrote:
> Brian Candler wrote:
>> Richard Fairbanks wrote:
>>> if p(Y.z): 0  # I assume this is the culprit!
>>>   osax.say(Y.z)    #=> silence
>>> end
>>
>> What are you trying to do here?
>
> Thank you for the response, Brian!
>
> (Y,z) is initially defined as 0:
>    module Y; def self.z; 0; end; end
>
> and both:
>    osax.say(Y.z)    #=> "zero" and
>    p(Y.z)  #=> {integer:0}
> validates that Y.z) = 0
>
> What if statement do I have to write to get Ruby to recognize an
> existing value?

if (Y.z == 0)
   osax.say(Y.z)
end

you have two errors:

p(Y.z) as Brian explained is calling Kernel#p which always returns
nil, and so using that return value in an if is not what you want. The
second error is using : 0, when you are trying (I think) to compare
the result of Y.z with 0. What follows the colon is the first
statement in the if body, not a value to compare to.

Jesus.