From: Amishera Amishera <amishera2007@...>
Date: 2010-04-01T07:28:41+09:00
Subject: Re: how to solve this regular expression problem

Amishera Amishera wrote:

> I can do this also:
> 
> s.gsub!(/#(\d+);/) { puts $1; conv_char($1) }
> 
> But I was wondering how to use both the \1 syntax and the function call 
> together in the gsub call in the first approach.

Okay it did solve half of the problem. Other half is how to display a
'\' infront.

s.gsub!(/#(\d+);/) { '\'+$1.to_i.to_s(8)}

is giving some compile error.
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