From: Robert Klemme <shortcutter@...>
Date: 2010-03-13T18:55:07+09:00
Subject: Re: Dir.glob problem

On 03/13/2010 01:40 AM, Michael W Ryder wrote:
> Michael W Ryder wrote:
>> David Vlad wrote:
>>> In the program Im making I need to read some wma files into a variable
>>> and I did like this:
>>>
>>> songs = Dir.glob("C:\\Users\\Public\\Music\\Sample Music\\*.wma")
>>>
>>> Note that this is NOT the wrong directory, I've copy pasted it from the
>>> map itself and also the files are wma and nothing else. My programming
>>> teacher has no idea why this dosnt work and the other ppl I've talked
>>> with dosnt know either. Most said something like "aside from a simple
>>> mistake like wrong directory/extension, I don't know what could be going
>>> wrong." So now this forum is my last resort, why on earth dosnt this
>>> work?!
>>
>> The only way I could get it to work is to use the example at 
>> http://ruby-doc.org/core/classes/Dir.html and create a directory 
>> variable such as: lfiles=Files.join("C:", "Users", "Public", "Music", 
>> "Sample Music", "*.wma") and then use a=Dir.glob(lfiles).
>> The only problem with that approach is that the entire path is added 
>> to each file.  I don't know if this is a concern or not.
> 
> Further experimenting found two other solutions.  The first is to use:
> a=Dir.glob("C:/Users/Public/Music/Sample Music/*.wma") which has the 
> same "problem" as my first solution.
> A better solution may be to use Dir.chdir to change to the directory and 
> then use Dir.glob to extract the file names.  This has the advantage of 
> not including the path in front of each file name.

You can use Dir.entries for that:

Dir.new("C:/Users/Public/Music/Sample Music").entries.grep /\.wma\z/i

Kind regards

	robert


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