From: Robert Klemme <shortcutter@...>
Date: 2010-03-09T17:12:08+09:00
Subject: Re: question on threads

2010/3/9 Jean G. <rubynewbee@gmail.com>:
> Hello,
>
> count = 0
> threads = []
>
> 10.times do |i|
>  threads[i] = Thread.new do
>    sleep(rand(0.1))
>    Thread.current["mycount"] = count
>    count += 1
>  end
> end
>
> threads.each {|t| t.join; print t["mycount"], ", " }
>
>
> For the code above, why the output numbers are random, rather than
> from 0 to 9 by increasing?

Because there are no guarantees about thread scheduling.  Btw, your
code is not really thread safe since you access a shared resource
without proper synchronization (although it might work on some Ruby
platforms).

Kind regards

robert


-- 
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/