From: Robert Klemme <shortcutter@...>
Date: 2010-02-25T05:50:25+09:00
Subject: Re: Create a counter in a hash to return first 10 results only

On 24.02.2010 20:52, John Dale wrote:
> John Dale wrote:
>> New to ruby..
>>
>> I created a hash array and everything works fine except I can't figure
>> out how to include a counter to return the first 10 results only.
>>
>> Thanks John
>>
>> Here is the code
>>
>> h = Hash.new
>> good_words.each { |w|
>>      if h.has_key?(w)
>>        h[w] = h[w] + 1
>>      else
>>        h[w] = 1
>>      end
>>    }
>>
>> # sort the hash by value, and then print it in this sorted order
>>
>> h.sort{|a,b| b[1]<=>a[1]}.each { |elem|
>>
>>     puts "\"#{elem[0]}\" has #{elem[1]} occurrences"
>>
>> }
>
>
> referred to an earlier post and figured this out.

Like?

h = Hash.new 0
...
h[w] += 1
...

puts h.sort_by {|w,c| -c}[0,10]

Kind regards

	robert


-- 
remember.guy do |as, often| as.you_can - without end
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