From: Zach Bartels <no@...>
Date: 2010-02-14T20:15:11+09:00
Subject: Re: Generating all possible combinations of a 5 digit pattern.

Geee, now I feel -real- dumb.   I appreciate that output, Sam.

-Zach



On Sat, 13 Feb 2010 22:02:51 -0500, Sam Roberts <vieuxtech@gmail.com>
wrote:

>>>On 2/13/2010 7:05 PM, Zach Bartels wrote:
>>>
>>>> I saw a very basic one or two line �example where a range of 3 letters
>>>> was given, equal to abc (I forgot how it was written) �and it pretty
>>>> much spat out �all the combos of those 3 letters.
>
>You have only two letters, C and N. That is like have only two digits,
>0 and 1. How many 5 digit combinations of 0 and 1 are there?
>
>2**5.
>
>So, count from 0 to 2**5-1, write the number in binary, then convert 0
>to C and 1 to N:
>
>irb(main):010:0> (0..(2**5-1)).map{|n| ("%05b" % n).tr("01", "CN") }
>=> ["CCCCC", "CCCCN", "CCCNC", "CCCNN", "CCNCC", "CCNCN", "CCNNC",
>"CCNNN", "CNCCC", "CNCCN", "CNCNC", "CNCNN", "CNNCC", "CNNCN",
>"CNNNC", "CNNNN", "NCCCC", "NCCCN", "NCCNC", "NCCNN", "NCNCC",
>"NCNCN", "NCNNC", "NCNNN", "NNCCC", "NNCCN", "NNCNC", "NNCNN",
>"NNNCC", "NNNCN", "NNNNC", "NNNNN"]
>
>Cheers,
>Sam