From: Dave Thomas <Dave@...>
Date: 2002-03-12T05:50:27+09:00
Subject: Re: painfully newbie question

Damien Joly <do_joly@yahoo.ca> writes:

> population = Array.new(5,Individual.new(1,0))

This line isn't doing what you think: it's initializing the array with
five references to the same individual object.

  population[0]---\__
  population[1]--\   \ 
  population[2]   -----> Invdividual.new()
  population[3]--/ __/
  population[4]---/


Try

  population = []
  5.times { population << Individual.new(1,0) }

or

  population = (1..5).collect { Individual.new(1,0) }


Cheers


Dave