From: Brian Candler <b.candler@...>
Date: 2010-01-16T02:09:44+09:00
Subject: Re: Public Key encryption

If it's an RSA key you can construct it from its parameters.

require 'openssl'
module OpenSSL
  module PKey
    class RSA

      # Construct an RSA key from parameters.
      # Input: a large number n
      #        an exponent
      # For private keys you also need:
      #        factor p of n
      #        factor q of n  (n = p * q)
      #        if d is nil then it is calculated from p and q

      def self.new_from_parameters(n, e, d=nil, p=nil, q=nil)
        a = self.new   # self.new(64) for ruby < 1.8.2
        a.n = n        # converted to OpenSSL::BN automatically
        a.e = e
        if p and q
          p,q = q,p if p < q
          a.p = p
          a.q = q
          raise "n != p * q" unless a.n == a.p * a.q
          a.d = d || a.e.mod_inverse((a.p-1)*(a.q-1))
          a.dmp1 = a.d % (a.p-1)
          a.dmq1 = a.d % (a.q-1)
          a.iqmp = a.q.mod_inverse(a.p)
        else
          a.d = d
          a.p = nil
          a.q = nil
        end
        a
      end
    end
  end
end

Then to convert it into a PEM format, all you need is:
puts OpenSSL::PKey::RSA.new_from_parameters(n, e)

The key you give is 1160 bits in total, maybe 1024 bits of product and 
136 bits of exponent? You'll need to find out its structure.
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