From: Aldric Giacomoni <aldric@...>
Date: 2010-01-14T02:32:30+09:00
Subject: Re: Bug with end of string characters in regex?

Justin Coyne wrote:
> /\A\n\Z/m.match("\n\n") => #<MatchData>
> 
> shouldn't this expression return nil?
> 
> 
> These both return nil.
> /\A\n\Z/m.match("a\n")
> /\A\n\Z/m.match("\na")
> 
> 
> My understanding is that \A and \Z always match at the beginning/end of
> the string irrespective of newlines.
> 
> -Justin

Check out rubular.com

You are asking for:

\A # beginning of string
\n # newline
\Z # end of string

And by the way ... "\n" and /\n/ may not be the same, depending on what 
the regexp wants to do with the backslash! you could try escaping it.
What do you want to match?
maybe:
/A # beginning of string
.* # any characters
\\n # newline
.* # any characters
/Z # end of string
-- 
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