From: Jeff Peng <jeffpeng@...>
Date: 2010-01-11T15:54:33+09:00
Subject: Re: Help

在 2010-01-11一的 15:30 +0900，Jagadeesh写道：
> Thanks Jeff. yes you are correct. But have a question
> 
> 

Because ruby is a strongly typed language while perl isn't.

In perl everything doesn't need to be pre-defined with specified type.
for example, a hash:

my %hash;
push @{$hash{key1}},"abc";


As you see above, though we didn't pre-define $hash{key1} as an
anonymous array, but perl does that for us silently.

But in ruby, you can't say:

hash = Hash.new
hash['key1'] << "abc"

This will get an error.
Instead we would say:

hash=Hash.new do |h,k| h['k'] = [] end
hash['key1'] << "abc"

This will work because we have passed a block to Hash.new method, this
block will set hash's every value to a seperate empty array []. After
that the array filling ("<<" in ruby) can run.

HTH.

Jeff.