From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2010-01-04T17:16:53+09:00
Subject: Re: how to capture all conditions using regex

On Mon, Jan 4, 2010 at 8:53 AM, Ruby Newbee <rubynewbee@gmail.com> wrote:
> Hello,
>
> irb(main):001:0> x="123 456 789"
> => "123 456 789"
>
> irb(main):003:0> if /\d{3}/ =~ x
> irb(main):004:1>   puts $&
> irb(main):005:1> end
> 123
>
>
> For the statement above, I want to capture all "123" and "456" and
> "789", not the only "123".
> How to do it (must use regex)? Thanks.

Use the scan method:

http://ruby-doc.org/core/classes/Kernel.html#M005985

irb(main):001:0> x="123 456 789"
=> "123 456 789"
irb(main):002:0> x.scan /\d{3}/
=> ["123", "456", "789"]

Jesus.