From: joe chesak <rubytalk@...>
Date: 2010-01-04T17:16:31+09:00
Subject: Re: how to capture all conditions using regex

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The regex itself seems okay...
irb(main):015:0> x.scan(/\d{3}/)
=> ["123", "456", "789"]


On Mon, Jan 4, 2010 at 8:53 AM, Ruby Newbee <rubynewbee@gmail.com> wrote:

> Hello,
>
> irb(main):001:0> x="123 456 789"
> => "123 456 789"
>
> irb(main):003:0> if /\d{3}/ =~ x
> irb(main):004:1>   puts $&
> irb(main):005:1> end
> 123
>
>
> For the statement above, I want to capture all "123" and "456" and
> "789", not the only "123".
> How to do it (must use regex)? Thanks.
>
>

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