From: Kvetch Kvetch <kvetch@...>
Date: 2010-01-04T13:58:37+09:00
Subject: Re: bitwise shift help

Actually I suppose the bit check should read
if ( x & y ) >= 1
Or I am still totally off.

Thanks

Kvetch Kvetch wrote:
> Hello, I am new to Ruby and was wondering if there is an easier/faster
> way to determine if a bit is set in a number. For example,
> If my number is 1011000010 and I want to check to see if 3rd bit is set
> so
> 1011000010
> 1000010000
> ----------
>       0000 - So 3rd bit is not set
> My code is
> 
> y = 1 << 3
> x = 0b1011000010
> 
> if ( x & y ) == 1
> puts "The 3rd bit is set"
> else
> puts "The 3rd bit is not set"
> end
> 
> Is there a better/faster method of achieving this bit check?
> Thank you

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