From: pharrington <xenogenesis@...>
Date: 2010-01-02T04:20:15+09:00
Subject: Re: Delete elements in array, break, and keep changes?

On Jan 1, 2:18 pm, pharrington <xenogene...@gmail.com> wrote:
> On Jan 1, 11:45 am, Joe Buck <semle2...@hotmail.com> wrote:
>
>
>
>
>
> > Ehsan,
>
> > Thanks for the help. Unfortunately I don't think that will work as it
> > removes the first element in the array.
>
> > What I need is an Array::delete_if or Array::reject! call that allows me
> > to break from the block while still removing elements.
>
> > My solution is to use a second array to keep the indices of all removed
> > elements. I can then iterate through the second array after the first
> > loop and remove the elements. I'm guessing reject! and delete_if do this
> > as well. It could be more efficient but it works.
>
> > Thanks!
> > --
> > Posted viahttp://www.ruby-forum.com/.
>
> Without knowing the point of what you're trying to do, this sounds
> like what you have in mind:
>
> array = [] # or whatev
> process_array = true
> array.reject!(x) do
>   if process_array
>     conditional_code_for x
>   else
>     false
> end

Also, is the reject! really the bottleneck in your app? We obviously
don't want to intentionally write sub-optimal code, but do not
optimize what's not slowing you down.