From: Robert Klemme <shortcutter@...>
Date: 2009-12-28T21:27:35+09:00
Subject: Re: unpack :(

2009/12/28 Brian Candler <b.candler@pobox.com>:
> Brian Candler wrote:
>>>> systemdate.unpack("nccccccAcc")
>> => [2009, 12, 28, 11, 42, 40, 0, "+", 1, 0]
>>
>> i.e. 11:42:40.0 (tenths of a second) with a timezone of +01:00
>
> Just to make this clear: you should not be using the "H" format
> converter. "H" gives you ASCII hex representation, for example the byte
> 0x07 is converted into the two ASCII characters "0" and "7", or vice
> versa.
>
> What you appear to have is a binary string, and you want the byte 0x07
> to be converted to the number 7, or the pair of bytes 0x07 0xd9 to be
> converted to the number 2009. These are the "c" and "n" formats
> respectively.

I am not so sure.  He said

> It's a hex string and It could be in these formats (for linux and
> windows):
>
> 2009-12-28,11:37:25.0,+1:0
> 2009-12-28,11:53:34.0

If it is actually a string, a completely different tool might better
suit the job:

require 'date'

[
  '2009-12-28,11:37:25.0,+1:0',
  '2009-12-28,11:53:34.0',
].each do |str|
  dt = DateTime.strptime str, '%Y-%m-%d,%H:%M:%S'
  printf "%s -> %p (%s)\n", str, dt, dt
end

That version omits time zone information though.

Cheers

robert


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