From: Brian Candler <b.candler@...>
Date: 2009-12-28T20:58:03+09:00
Subject: Re: unpack :(

Alfonso Caponi wrote:
> With systemDate = systemDate.unpack("H*") I've 07d90c1c0b2a28002b0100,
> where 07d9 is 2009 in decimal, 0c is 12, 1c is 28 and so on.. :(

It would still be easier if you showed the original string, but I'm 
guessing it's this:

>> systemdate = ["07d90c1c0b2a28002b0100"].pack("H*")
=> "\a\331\f\034\v*(\000+\001\000"
>> systemdate.bytes.to_a
=> [7, 217, 12, 28, 11, 42, 40, 0, 43, 1, 0]

In that case:

>> systemdate.unpack("nccccc")
=> [2009, 12, 28, 11, 42, 40]

I'm not sure how you want the last 4 bytes interpreted, but a bit of 
googling for SNMP systemDate suggests the following:

>> systemdate.unpack("nccccccAcc")
=> [2009, 12, 28, 11, 42, 40, 0, "+", 1, 0]

i.e. 11:42:40.0 (tenths of a second) with a timezone of +01:00
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