From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2009-12-14T19:16:24+09:00
Subject: Re: problem with trivial regular expression

On Mon, Dec 14, 2009 at 11:06 AM, David Villa <villa.hxc@gmail.com> wrote:
>
> hi ,sorry for my english.
>
> I am trying to remember the use of regular expressions and i have a
> problem  with this  :
>
> i had a text with diferents strings, for example, url , like this :
>
> fajljsfjaosfohttp://www.marca.comjafosjodfahttp://www.as.comjfoaasjofja
>
> i want to extract the diferents url  but i try with :
> /(http\:\/\/.+com)/ it returns a long match:
>
>
>
>   1. http://www.marca.comjafosjodfahttp://www.as.com
>
>
> how can i group this in 2 diferents matchs? example :
> 1- http://www.marca.com
> 2- http://www.as.com
>
>
> thanks
> --
> Posted via http://www.ruby-forum.com/.
>
>

What you are missing is the non-greedy modifier (?) for the +:

irb(main):001:0> s = "
fajljsfjaosfohttp://www.marca.comjafosjodfahttp://www.as.comjfoaasjofja"
=> " fajljsfjaosfohttp://www.marca.comjafosjodfahttp://www.as.comjfoaasjofja"
irb(main):003:0> s.scan(/http\:\/\/.+?\.com/)
=> ["http://www.marca.com", "http://www.as.com"]

(I also added an extra \. before com, to match a ".com" and not "com"
only). Then, scan helps you going through the full string retrieving
matches.

Hope this helps,

Jesus.