From: Benoit Daloze <eregontp@...>
Date: 2009-12-13T23:19:51+09:00
Subject: Re: Code block for element comparison in an array?

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Here the solution with Integer#upto(n), as mentioned by Robert.

0.upto(array.length-1) { |i|
  (i+1).upto(array.length-1) { |j|
    // Comparison here!
  }
}

And the first loop could be replace by array.length.times { |i| }
Or even better, array.each_index { |i| }

That looks more rubyish ...

P.S.: You can use 0...array.length instead of 0..array.length-1

2009/12/13 Derek Cannon <novellterminator@gmail.com>

> Ah, I figured it out... For anyone who is interested the answer is:
>
> for i in 0..array.length-1
>   for j in i+1..array.length-1
>     // Comparison here!
>   end
> end
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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