From: Robert Gleeson Date: 2009-12-12T19:23:35+09:00 Subject: Re: a question on method name > x = Foo.new.bar= 1,2,3 # => [1,2,3] > x.bar # => "123" Oops. If you want that to work as-is.. x = Foo.new x.bar= 1,2,3 # => [1,2,3] x.bar # => "123" - Rob -- Posted via http://www.ruby-forum.com/.