From: Intransition <transfire@...>
Date: 2009-12-08T14:10:23+09:00
Subject: Re: Regexp.escape with un-escapes



On Dec 6, 12:45 pm, Brian Candler <b.cand...@pobox.com> wrote:
> There is a feature in String#split (documented in 1.9, undocumented in
> 1.8.6 but still present) whereby if the split RE contains capture
> groups, those capture groups will be included in the resulting array.
>
> >> s = 'here is (a) setting \'a\' equal to ((\d+))'
>
> => "here is (a) setting 'a' equal to ((\\d+))">> Regexp.new(s.split(/(\(\(.*?\)\))/).map { |x| x =~ /\A\((\(.*\))\)\z/ ? $1 : Regexp.escape(x) }.join)
>
> => /here\ is\ \(a\)\ setting\ 'a'\ equal\ to\ (\d+)/

Weird, but cool. Does the trick. Thanks.