From: "Michael W. Ryder" <_mwryder55@...>
Date: 2009-12-03T10:20:12+09:00
Subject: Re: Increment outerloop value in innerloop in each do Syntax

Nag Raj wrote:
> Hi All,
> 
> I am new to RUBY. Please help me in solving the below problem.
> I have a c code and I am trying to do the same in RUBY.
> 
>    for(int i = 0; i < 10;i++)
>    {
>       for(int j = 0; j< 5; j++)
>       {
>          if(i == j)
>          {
>             printf("%d - its J value\n",j);
>             i++;
>          }
>       }
>       printf("%d - its I value\n",i);
>    }
> 
> Above is my C code. The output of above code is:
> 
> 0 - its J value
> 1 - its J value
> 2 - its J value
> 3 - its J value
> 4 - its J value
> 5 - its I value
> 6 - its I value
> 7 - its I value
> 8 - its I value
> 9 - its I value
> 
> I want to do the same in RUBY. I have written following script
> 
> (0..9).each do |i|
>    (0..5).each do |j|
>       if( i == j)
>          puts "#{j} J Value"
>       end
>    end
>    puts "#{i} I Value"
> end
> 
> But its not giving the desired output. Please suggest me how to achieve
> the above output using RUBY script.
>

I don't think you can use each on the i value.  I would use a while loop 
to check for the value of i.


> Thanks in advance.
> 
> Regards,
> Nag.