From: Benoit Daloze <eregontp@...>
Date: 2009-11-27T06:55:28+09:00
Subject: Re: Help with regex

--0016e6482b2691405404794d3b55
Content-Type: text/plain; charset=ISO-8859-1

s = "Text1\n
Text2\n
Text3---"

irb(main):036:0> s.scan( /(\w+?)(?:\n|-+)/ )
=> [["Text1"], ["Text2"], ["Text3"]]

Usually, it's easier to use scan when you feel your code in the Regexp gonna
be repeated.
If the text is so simple, you could iterate which String#each_line, and then
remove any '-' at the end.

2009/11/26 Lucas Fialho <lucasfazprograma@gmail.com>

> Hello everyone.
> I'm trying to match the following pattern:
>
> Text1\n
> Text2\n
> Text3---
>
> Please note that Text3 can contain \n.
> I tried using this regex:
>
> /(.*?)\n(.*?)\n(.*?)---/
>
> The pattern matches and I have three matches, but they're like this:
>
> match[0] => "Text2\nText3---"
> macth[1] => 'Text2'
> match[2] => 'Text3'
>
> How can I get the first one to be 'Text1' ?
>

--0016e6482b2691405404794d3b55--