From: Seebs <usenet-nospam@...>
Date: 2009-11-22T07:30:12+09:00
Subject: Order of evaluation and precedence

In _The Ruby Programming Language_, it is asserted that order of evaluation
is controlled by precedence.

However, this is often asserted in books about C, where it's definitely
not true.  Is it actually true in Ruby?

In other words:

	def a
	  puts "a"
	  1
	end
	def b
	  puts "b"
	  1
	end
	def c
	  puts "c"
	  1
	end
	x = a + (b + c)

Is it actually guaranteed that the output will have "a" after "b" and "c"?
In C, it wouldn't be.  (Compilers are free to evaluate the operands in any
order whatsoever, then feed them into operators, all that precedence and
grouping controls is which operands go to which operators.)

-s
-- 
Copyright 2009, all wrongs reversed.  Peter Seebach / usenet-nospam@seebs.net
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