From: dmcnulty@... (Dan McNulty)
Date: 2002-03-01T22:12:58+09:00
Subject: Re: Correct use of % (modulus) operator?

Ack, quite right.  So I haven't actually *used* C for awhile :-)

I wonder what operator or function I am recalling that yields a
floating point remainder....oh well, its not important anyway.

Thanks to all for being gentle.

-- Dan


Josh Huber <huber@alum.wpi.edu> wrote in message news:<87elj4g7cd.fsf@paradoxical.net>...
> dmcnulty@mindspring.com (Dan McNulty) writes:
> 
> > Coming from a C background, I expected "%" to yield a remainder.
> 
> Coming from a C background, I would have expected you to expect this
> result! ;)
> 
> > But the code:
> > print "4 mod 2: ", 4.0 % 2.0, "\n"
> > print "5 mod 2: ", 5.0 % 2.0, "\n"
> >
> > gives me:
> > 4 mod 2: 0.0
> > 5 mod 2: 1.0
> >
> > I was expecting a result of "0.5" for 5 % 2, as 5.0 / 2.0 = 2.5
> >
> > This isn't covered very well in the books I have, nor can I find much
> > on the 'net.  I obviously have missed something rather fundamental.
> 
> 5 % 2 = 1 because 2 goes into 5 twice, with 1 remaining.
> 
> IOW, the % operator is for *integer* remainder only. (just as in C)
> 
> ttyl,