From: Benoit Daloze <eregontp@...>
Date: 2009-11-12T04:59:29+09:00
Subject: Re: Roman Numerals (Arrgh!)

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Well, being student as well, I'd love to study Ruby instead of this (****)
Java. (Where are you studying?) But that's not the point.

So, here is my piece of advice:

Using $numerals = [
  [1000, "M"], [900, "CM"], [500, "D"], [400, "CD"],
  [100,  "C"], [90,  "XC"], [50,  "L"], [40,  "XL"],
  [10,   "X"], [9,   "IX"], [5,     "V"], [4,   "IV"],
  [1,    "I"]
]

,you should iterate on each of them, seeing how much your number have of
this kind (/)
and what is the rest after that, to use it for the next step(%)...
(if you use Array#each, you'll get a new array(let's say a) like a=[dec,
romanString]. You can then take them separetely by a[0] and a[1].
Even if this method is not that beautiful in Ruby, it's the easiest way to
understand how to do it).

That the way used in a very known book of Ruby.

You just need to manage how to save this in your String at each step.
(You can multiply a String by "X" * 3, and concatenate using << (or +=))

Give us your script when you'll got one working ;)

Hope you'll find this tip usefull,

Benoit

2009/11/11 Paul Smith <paul@pollyandpaul.co.uk>

> On Wed, Nov 11, 2009 at 4:17 PM, Gennady Bystritsky
> <Gennady.Bystritsky@quest.com> wrote:
> >
> > On Nov 11, 2009, at 7:56 AM, Paul Smith wrote:
> >
> >>>
> >>> Now you intrigued me ;-). So I am asking directly -- given the
> following $numerals:
> >>> $numerals = [[1000, "M"], [500, "D"], [100, "C"], [50, "L"], [10, "X"],
> [5, "V"], [1, "I"]]
> >>
> >> $numerals = [[1000, "M"], [900, "CM"], [500, "D"], [400, "CD"], [100,
> >> "C"], [90, "XC"], [50, "L"], [40, "XL"], [10, "X"], [9, "IX"], [5,
> >> "V"], [4, "IV"], [1, "I"]]
> >
> > Oops, true. No morning coffee takes its dues ;-) -- I suspected that's
> what was implied, however somehow started thinking that the 2-character
> strings might be multiplied by that algorithm. My bad, it works indeed.
>
> Yes indeed, you can't get doubles of the 2 character strings, because
> their values are always more than half of the preceeding value.  In
> other words, inorder to get a "CMCM" type mistake, your value must be
> at least 1800.  But if it's at least 1800, you'd still be processing
> the M's.
>
> >
> > Thank you guys,
> > Gennady.
> >
> >>
> >>>
> >>> ...how one can transform it so that the original algorithm would
> produced shortened roman numbers? Please present the exact value of
> $numerals satisfying the above condition.
> >>>
> >>> Gennady.
> >>>
> >>
> >>
> >>
> >> --
> >> Paul Smith
> >> http://www.nomadicfun.co.uk
> >>
> >> paul@pollyandpaul.co.uk
> >>
> >
> >
> >
>
>
>
> --
> Paul Smith
> http://www.nomadicfun.co.uk
>
> paul@pollyandpaul.co.uk
>
>

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