From: Harry Kakueki <list.push@...>
Date: 2009-11-08T21:19:43+09:00
Subject: Re: A method that doesn't change its arguments

On Sun, Nov 8, 2009 at 7:40 PM, Timo Jeranko <jeranko@gmail.com> wrote:
> At the moment I'm doing something like this:
>
> def some_method(array1)
>  ...
>  array2 = array1.clone
>  ...
>  array2.delete_at(i)
>  ...
>  return array2
>  ...
> end
>
>
> I would like array1 to remain unchanged. It seems a little inefficient
> to clone array1 every time some_method is called.  Is there a more
> elegant solution?
>

Couldn't you do something like this?

arr1 = ("a".."j").to_a
i = 3
p arr1[0...i]+arr1[i+1..-1]    #> ["a", "b", "c", "e", "f", "g", "h", "i", "j"]


Harry
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