From: Harry Kakueki <list.push@...>
Date: 2009-10-19T08:00:24+09:00
Subject: Re: Dynamic nested each in ruby 1.8.7?

On Mon, Oct 19, 2009 at 6:46 AM, Toi Toi <toi@mailinator.com> wrote:
> That function does not give the correct output for larger arrays. The
> level functions can be generated with eval, see the code below. However
> there must be a better Ruby way.
>
> def calc level
>  tmp = ["def calcd nums\ntmp=[]\n"]
>  str = "n1"
>  num = 1
>
>  level.times {
>    tmp.push "nums.each{ |n#{num}| tmp.push #{str}\n"
>    str = str+" + n#{num+=1}"
>  }
>  level.times { tmp.push "}"}
>
>  tmp.push "\ntmp\n"
>  tmp.push "end"
>  tmp.to_s
> end
> array, times = ('1'..'10').to_a, 3
> eval(calc(times))
> p calcd(array)
>



def calc_new(arr,l)
  h,t = Hash[*(0...arr.size).zip(arr).flatten],[]
  (1..l).each do |z|
    (0...arr.size**l).each do |x|
      t << x.to_s(arr.size).rjust(z,"0")
    end
  end
  t.uniq.sort.map{|c| c.split(//).map{|d| h[d.to_i]}.join}
end

p calc_new((1..10).to_a, 3)


Harry

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