From: Toi Toi <toi@...>
Date: 2009-10-19T06:46:26+09:00
Subject: Re: Dynamic nested each in ruby 1.8.7?

That function does not give the correct output for larger arrays. The 
level functions can be generated with eval, see the code below. However 
there must be a better Ruby way.

def calc level
  tmp = ["def calcd nums\ntmp=[]\n"]
  str = "n1"
  num = 1

  level.times {
    tmp.push "nums.each{ |n#{num}| tmp.push #{str}\n"
    str = str+" + n#{num+=1}"
  }
  level.times { tmp.push "}"}

  tmp.push "\ntmp\n"
  tmp.push "end"
  tmp.to_s
end
array, times = ('1'..'10').to_a, 3
eval(calc(times))
p calcd(array)


Harry Kakueki wrote:
> On Sun, Oct 18, 2009 at 11:43 AM, Toi Toi <toi@mailinator.com> wrote:
>>      }}}
>>  tmp
>> end
>>
>> puts calc(["0", "1"], 3)
>> --
> 
> Does this give you the right output?
> No recursion, but...
> 
> def calc(n, v)
>   h,t = Hash[*(0...n.size).zip(n).flatten],[]
>   (1..v).each{|x| (0...n.size**x).each{|y| t << 
> y.to_s(n.size).rjust(x,"0")}}
>   t.map{|a| a.split(//).map{|b| h[b.to_i]}.join}.sort
> end
> 
> p calc(["0","1"], 3)
> 
> 
> Harry

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