From: Josh Cheek <josh.cheek@...>
Date: 2009-10-01T23:00:13+09:00
Subject: Re: Group by unique entries of a hash

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On Thu, Oct 1, 2009 at 8:15 AM, Ne Scripter <stuart.clarke@northumbria.ac.uk
> wrote:

> I am having real problems with my array. As expected my array contents
> is like so:
>
> "00000004 00000005"
> "00000003 00000006"
> "00000001"
> "00000002"
>
> I now want 6 indivdual elements insteal of 4. I have tried to split the
> double entries up with split, however they remain together. Is there
> something fundamental I am missing? I want an array like so
>
> array = ["00000004", "00000005", "00000003", "00000006", "00000001",
> "00000002"]
>
> Sorry if this is simple, I have spent several hours chopping and
> changing.
>
> Thanks
>
> S
>
> David A. Black wrote:
> > On Thu, 1 Oct 2009, Simon Krahnke wrote:
> >
> >> or
> >>
> >> hash, ocrID, *ignored = *data.split(",")
> >>
> >> if you want to ignore everything behind a second comma, or
> >>
> >> hash, ocrID = *data.split(",", 2)
> >>
> >> if you want to include a second comma and everything behind it into the
> >> ocrID string.
> >
> > I don't think you need the * for any of them. This:
> >
> >    hash, ocrID = data.split(',')
> >
> > should be fine for getting the first two values.
> >
> >
> > David
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

x = [
  "00000004 00000005"  ,
  "00000003 00000006"  ,
  "00000001"           ,
  "00000002"           ,
]

x.map!{|str| str.split(/\s+/) }.flatten!

x # => ["00000004", "00000005", "00000003", "00000006", "00000001",
"00000002"]

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