From: Ne Scripter <stuart.clarke@...>
Date: 2009-10-01T22:15:16+09:00
Subject: Re: Group by unique entries of a hash

I am having real problems with my array. As expected my array contents 
is like so:

"00000004 00000005"
"00000003 00000006"
"00000001"
"00000002"

I now want 6 indivdual elements insteal of 4. I have tried to split the 
double entries up with split, however they remain together. Is there 
something fundamental I am missing? I want an array like so

array = ["00000004", "00000005", "00000003", "00000006", "00000001", 
"00000002"]

Sorry if this is simple, I have spent several hours chopping and 
changing.

Thanks

S

David A. Black wrote:
> On Thu, 1 Oct 2009, Simon Krahnke wrote:
> 
>> or
>>
>> hash, ocrID, *ignored = *data.split(",")
>>
>> if you want to ignore everything behind a second comma, or
>>
>> hash, ocrID = *data.split(",", 2)
>>
>> if you want to include a second comma and everything behind it into the
>> ocrID string.
> 
> I don't think you need the * for any of them. This:
> 
>    hash, ocrID = data.split(',')
> 
> should be fine for getting the first two values.
> 
> 
> David

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