From: "David A. Black" <dblack@...>
Date: 2009-10-01T02:14:31+09:00
Subject: Re: Group by unique entries of a hash

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On Thu, 1 Oct 2009, Simon Krahnke wrote:

> * Paul Smith <paul@pollyandpaul.co.uk> (2009-09-29) schrieb:
>
>>> � �fields = data.split(",")
>>> � �hash = fields[0]
>>> � �ocrID = fields[1]
>
> BTW, you could write this as:
>
> hash, ocrID = *data.split(",")
>
> or
>
> hash, ocrID, *ignored = *data.split(",")
>
> if you want to ignore everything behind a second comma, or
>
> hash, ocrID = *data.split(",", 2)
>
> if you want to include a second comma and everything behind it into the
> ocrID string.

I don't think you need the * for any of them. This:

   hash, ocrID = data.split(',')

should be fine for getting the first two values.


David

-- 
David A. Black, Director
Ruby Power and Light, LLC (http://www.rubypal.com)
Ruby/Rails training, consulting, mentoring, code review
Book: The Well-Grounded Rubyist (http://www.manning.com/black2)
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