From: Semih Ozkoseoglu <ozansemih@...>
Date: 2009-09-27T09:15:19+09:00
Subject: Re: Roulette & rand

Excuse my ignorance,

After running the above code  a few times I realized that the bet_rand 
and bet_red was always EXACTLY the same. So I realized that there was 
something wrong with the code. bet_rand somehow behaves exactly the same 
way as bet_red. I don't know whats wrong with it but it doesn't matter.

> One problem that I can see is that you're allowing your random betting
> strategy to pick 0, rather than red or black, which I don't think is
> your intention.
> 
> Change
> 
>>  number_02 = rand(37)
>>  color_02 = colors[number_02]
> 
> to
> 
> color_02 = [:red, :black][rand(2)]


Here is the fixed code with Paul's suggestion

colors = {}
[2, 4, 6, 8, 10, 11, 13, 15, 17, 20, 22, 24, 26, 28, 29, 31, 33, 
35].each do |i|
  colors[i] = :black
end
[1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36].each 
do |i|
  colors[i] = :red
end
  colors[0] = :zero

bet_rand = 0
bet_red = 0

puts 'How many rolls to simulate'
number_of_rolls = gets.chomp.to_i

number_of_rolls.times do

  number_01 = rand(37)
  color_01 = colors[number_01]
  color_02 = [:red, :black][rand(2)]

  if color_01 == :red
    bet_red += 1
  else
    bet_red -= 1
  end

  if color_02 == color_01
    bet_rand += 1
  else
    bet_rand -= 1
  end
end

puts bet_rand
puts bet_red
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