From: Paul Smith <paul@...>
Date: 2009-09-24T19:02:50+09:00
Subject: Re: email regex

[^.@\s,]

This character class excludes "." "@" whitespace and "," from being in
the first part of the e-mail.

Remove the dot and sijo.kg@yahoo.com will be allowed.

[^@\s,]

/^([^@\s,]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})$/i

However, sijo..kg@yahoo.com will also be allowed.  It's up to you here
- do you want to make the regex perfect or will this be good enough.

I think what you want is a optional repeating sequence of characters
followed by exactly 1 "." followed by a final sequence of characters
before the @

Something like this

/^((?:[^@\s,]+.)*[^@\s,]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})$/i

Maybe?

Though you probably need to read here:
http://www.regular-expressions.info/email.html
http://blog.krugle.com/?p=208


On Thu, Sep 24, 2009 at 10:48 AM, Sijo Kg <sijo@maxxion.com> wrote:
> Hi
>
>    I have a regular expression
> /^([^.@\s,]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})$/i
>
> This exactly fits my need except for one.
>
>     But I have to pass this also   sijo.kg@yahoo.com      But Cannot.
> Please help me to add this also to the above
>
> Some example which are valid for above
> sijo@yahoo.com
> sijo@yahoo.co.uk
>
> Some example which are not valid for above
> .sijo@yahoo.com
> sijo..kg@yahoo.com
> sijo@@yahoo.com
>
>
> Thanks in advance
> Sijo
> --
> Posted via http://www.ruby-forum.com/.
>
>



-- 
Paul Smith
http://www.nomadicfun.co.uk

paul@pollyandpaul.co.uk