From: John W Higgins <wishdev@...>
Date: 2009-09-17T03:21:48+09:00
Subject: Re: string to array

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On Wed, Sep 16, 2009 at 10:50 AM, Re BR <rereis@hotmail.com> wrote:

> John W Higgins wrote:
> > On Wed, Sep 16, 2009 at 9:20 AM, John W Higgins <wishdev@gmail.com>
> > wrote:
> >
> >> >
> >> x = "apple-orange-grape"
> >> tmp = x.split('-')
> >> (0..tmp.length-1).map{ |i| e[i..-1].join('-') }
> >>
> >
> > Sorry that should be
> >
> > (0..tmp.length-1).map{ |i| tmp[i..-1].join('-') }
> >
> > John
>
> trying to make this as a one liner
>
> a.split('.').map{ |i| a[i..-1].join('.') }
>
> but I am missing something
>

There are two problems here. First, the a[i..-1] concept needs the array
from a.split('.') to work and therefore you need to store it. Also, the map
doesn't give you the indexes which is what the i is here. The a[i..-1] works
by creating an array of each element till the end so you want the index
which is not what the .map in this case will give you.

I'm not sure there is a one liner method going down this road. Maybe the
regex options would work that way but not the split and rejoin concept (at
least I couldn't get it there).

John

>

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