From: -j b- <jrb562@...>
Date: 2009-09-08T23:37:04+09:00
Subject: Shellwords preserve backslash

I am trying to parse a string that is formatted with DOS-like file
names.
For instance:

   s = "a b c d \"C:\\user\\sub_dir\" \"C:\\user\\other_dir\""

When I use Shellwords.shellwords(s) however, I get the following:

   Shellwords.shellwords(s)
   => ["a", "b", "c", "d", "C:usersub_dir", "C:userother_dir"]

I have also tried Shellwords.escape(s) which yields:

   Shellwords.escape(s)
   => "a\\ b\\ c\\ d\\ \\\"C:\\\\user\\\\sub_dir\\\"\\
\\\"C:\\\\user\\\\other_dir\\\""

Which is not parsed correctly by shellwords (I get back a string rather
than an array). What I would like to do is is to preserve the
"C:\user\sub_dir" format and I am stumped on how to do so. I tried a
gsub on the string before sending it to shellwords but that seemed to
preserve nothing. Something similar to

   Shellwords.shellwords(s.gsub('\\', '\\\\\\'))
   => ["a", "b", "c", "d", "C:usersub_dir", "C:userother_dir"]

It might be of interest that Shellwords.shellwords(s) worked in my
version of 1.8.7. I just updated to the latest stable release (1.9.1)
and ran into this roadblock.
Searching the list logs turned up little.
Any suggestions?

Thanks in advance.
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