From: 7stud -- <bbxx789_05ss@...>
Date: 2009-09-07T13:06:15+09:00
Subject: Re: i need to strip \n and nil

7stud -- wrote:
> Bigmac Turdsplash wrote:
>> 7stud -- wrote:
>>> Michael Fellinger wrote:
>>>>
>>>> 
>>>> ["59023\n", nil].join.to_i
>>> 
>>> You're kidding, right?
>> 
>> I had it figured out a few minutes after this post... i didnt know the 
>> differnce between a string and array... i convert the array to a string 
>> then used compact
>> 
> 
> Ridiculous.  You would never compact an array just to get the first 
> element.  If you want the first element, then grab it.  See Bertram's 
> posts.
> 
> 
>> i thought i was working the string class so i was reading threw the 
>> wrong page...
>> 
>> any ways... because of this premature post, i spent a few hours try to 
>> solve a new problem before i ask for help...
>> 
>> strings="a9digh0t5"
>> # every 3 bytes i need broke into separate strings[x]
>> puts(string[1]) #==> a9d
>> puts(string[2]) #==> ihg
>> puts(string[3]) #==> 0t5
>> 
>> how can i brake a long string into blocks equal to 3 bytes?
> 
> If the length of the string will always be a multiple of 3, you can do 
> this:
> 
> str = "a9digh0t5"
> 
> str.scan(/.{3}/) do |substr|
>   puts substr
> end
> 
> --output:--
> a9d
> igh
> 0t5
> 
> 
> Otherwise, you'll have to deal with ruby's infernal each_byte() method.

Actually, you can take advantage of a regex's greedy nature, and do this 
instead:

str = "a9digh0t5xx"

str.scan(/.{1,3}/) do |substr|
  puts substr
end

--output:--
a9d
igh
0t5
xx

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