From: "David A. Black" <dblack@...>
Date: 2009-08-27T08:05:20+09:00
Subject: Re: ||= with 1.8 and 1.9 ?

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Hi --

On Thu, 27 Aug 2009, Rick DeNatale wrote:

> On Wed, Aug 26, 2009 at 5:23 PM, David A. Black<dblack@rubypal.com> wrote:
>> It isn't, though, at least in the ||= case (see Joel W.'s post).
>> Matz's characterization of it to me at RubyConf (or somewhere) was:
>>
>> �x ||= y � same as � �x || x = y
>
> It's approximately the same as certainly closer than x = x || y
>
> There's a difference in what happens if x is not previously defined

True. Maybe this?

   defined?(x) && x || x = y


David

-- 
David A. Black / Ruby Power and Light, LLC / http://www.rubypal.com
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