From: Rick DeNatale <rick.denatale@...>
Date: 2009-08-27T07:20:33+09:00
Subject: Re: ||= with 1.8 and 1.9 ?

On Wed, Aug 26, 2009 at 5:23 PM, David A. Black<dblack@rubypal.com> wrote:
> It isn't, though, at least in the ||= case (see Joel W.'s post).
> Matz's characterization of it to me at RubyConf (or somewhere) was:
>
>  x ||= y   same as    x || x = y

It's approximately the same as certainly closer than x = x || y

There's a difference in what happens if x is not previously defined


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Rick DeNatale

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