From: 7stud -- <bbxx789_05ss@...>
Date: 2009-08-21T19:10:38+09:00
Subject: Re: [regexp] How to convert string "/regexp/i" to /regexp/i

Joao Silva wrote:
> When i try to use:
> 
>>> Regexp.new("/regexp/i")
> => /\/regexp\/i/
> 
> But it's not what i want - i need:
> 
> /regexp/i
> 
> :-(
> 
> How i can convert this proper way?

str = "/regexp/i"
pieces = str.split("/")
pattern = pieces[1]

my_regex = Regexp.new(pattern, true)

md = my_regex.match("hello ReGexP")
puts md[0]

--output:--
ReGexP


Or, more generally:

str = "/reg.*?exp/im"
pieces = str.split("/")
pattern = pieces[1]
flags = pieces[2]

arg_two = 0

flags.length.times do |i|
  case flags[i, 1]
  when "i"
    arg_two |= Regexp::IGNORECASE
  when "m"
    arg_two |= Regexp::MULTILINE
  when "x"
    arg_two |= Regexp::EXTENDED
  end

end

regex = Regexp.new(pattern, arg_two)

test_str =<<ENDOFSTRING
hello rEG
world exP
ENDOFSTRING

md = regex.match(test_str)
if md
  puts md[0]
end

--output:--
rEG
world exP

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