From: Harry Kakueki <list.push@...>
Date: 2009-08-06T08:11:47+09:00
Subject: Re: zero placeholder exponential sprintf?

>
> We have a request for 0.112345e+02 instead of,
>
>  % ruby -e "puts '%.6e' % [ 1.123450e+2 ]"
>  1.123450e+02
>
> Possible?
>

Sorry for posting yet again.
Just a little adjustment.
I'll stop now.


x = 1.12345e2

s,y,h = 7, Math.log10(x).floor+1,{-1=>"e-",0=>"e+",1=>"e+"}
p (x*10**(y*-1)).to_s[0..s+1].ljust(s+2,"0")+h[(y<=>0)]+y.abs.to_s.rjust(2,"0")


Harry


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