From: Jason Lillywhite <jason.lillywhite@...>
Date: 2009-08-02T12:58:00+09:00
Subject: build array from interval and duration

Is there a shorter way to build an array based on an interval and
duration than the way I attempted?

def build_array(step,duration)
  counter = 0
  a = []
  while counter <= duration do
    a << counter
    counter += step
  end
  return a
end

irb(main):010:0> dt = 0.5
=> 0.5
irb(main):011:0> total_time = 10
=> 10
irb(main):012:0> time_steps = build_array(dt,total_time)
=> [0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0, 4.5, 5.0, 5.5, 6.0, 6.5,
7.0, 7.5, 8.0, 8.5, 9.0, 9.5, 10.0]


Thank you!
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