From: ddoherty03 <ddoherty03@...>
Date: 2009-07-23T04:25:06+09:00
Subject: Re: Bug Rounding Floats? (9.245 * 100).round => 924? S/B 925!

On Jul 22, 1:13 pm, Glenn Jackman <gle...@ncf.ca> wrote:
> A workaround, convert the expression to a string and back to a number:
>
>     num = Float("%.1f" % (9.245 * 100)).round
>
>     puts "yippee" if num == 925
>

Glenn,

Thanks for the explanation.  If I could pick your brain for a second
on how to generalize your workaround, I would greatly appreciate it.

Here is how I tried to implement the "nround" method.

######################################
class Float
  def nround(n = 0)
    (self * 10.0 ** n).round / 10.0 ** n
  end
end
######################################

My issue is getting the workaround to deal with the parameter n
properly.

Regards,