From: Mark Thomas <mark@...>
Date: 2009-07-21T21:25:06+09:00
Subject: Re: XML output (urgent)

On Jul 20, 10:13 pm, Hv Mai <longmai2...@yahoo.com.au> wrote:
> Hi all,
>
> >> t = {'type' => 'abc', 'numbers' => {'number' => [333], 'src' => 'glasses'}}
>
> => {"type"=>"abc", "numbers"=>{"number"=>[333], "src"=>"glasses"}}>> puts XmlSimple.xml_out({"policyDetails" => t},{"KeepRoot" => true})
>
> <policyDetails type="abc">
>   <numbers src="glasses">
>     <number>333</number>
>   </numbers>
> </policyDetails>
>
> Can you please give me a hint that how to output the xml likes below ...
>
> >> puts XmlSimple.xml_out({"policyDetails" => t},{"KeepRoot" => true})
>
> <policyDetails type="abc">
>   <numbers src="glasses">333</numbers>
> </policyDetails>

The trick with XmlSimple is that it can round-trip. In other words,
you can perform xml_in() on the output you want and you'll see exactly
what you need for xml_out() to produce it.

so, you can do this:

  require 'xmlsimple'
  data = '<policyDetails type="abc">
            <numbers src="glasses">333</numbers>
          </policyDetails>'

  xml = XmlSimple::xml_in(data, {"KeepRoot" => true})

  p xml

and you'll get

  {"policyDetails"=>[{"type"=>"abc", "numbers"=>[{"src"=>"glasses",
"content"=>"333"}]}]}

and therefore, if you perform xml_out on the above like so:

  data = {"policyDetails"=>[{"type"=>"abc", "numbers"=>
[{"src"=>"glasses", "content"=>"333"}]}]}
  puts XmlSimple::xml_out(data, {"KeepRoot" => true})

you get:

  <policyDetails type="abc">
    <numbers src="glasses">333</numbers>
  </policyDetails>

...exactly what you want.

-- Mark.

P.S. I hadn't used XmlSimple before, but the docs on the xml_out
method say "If the resulting XML is parsed using xml_in, it will
return a data structure equivalent to the original." so I realized the
above trick would work.