From: Tom Cloyd <tomcloyd@...>
Date: 2009-07-17T07:01:07+09:00
Subject: Re: case statement puzzle

Bertram Scharpf wrote:
> Hi,
>
> Am Freitag, 17. Jul 2009, 02:12:27 +0900 schrieb Tom Cloyd:
>   
>> James Coglan wrote:
>>     
>>> 2009/7/16 Tom Cloyd <tomcloyd@comcast.net>
>>>       
>>>> x='1'
>>>> case
>>>> when x =='0'
>>>>  puts '0'
>>>> when (1..5).include? x.to_i
>>>>  puts '1'
>>>> end
>>>>         
>>> What about:
>>>
>>> x='1'
>>> case
>>> when x =='0'
>>>  puts '0'
>>> when '1'..'5'
>>>  puts '1'
>>> end
>>>
>>>       
>> THANKS! That's the "missing piece" - I need to study up on "===", about 
>> which I know nothing.
>>     
>
> This will output "1" because the Range object '1'..'5' is not nil
> and not false. It has nothing to do with the === operator. You
> could also write
>
>   x='1'
>   case
>     when x == '0'
>       puts '0'
>     when "hi, there"
>       puts '1'
>   end
>
> To apply the === operator you have to mention the variable
> after the "case" keyword.
>
>   x = '1'
>   case x
>     when '0'      then puts '0'
>     when '1'..'5' then puts '1'
>   end
>
> Bertram
>
>
>   
Thanks...you're right, of course, and I soon learned that, in this 
morning ruby exercise session. Very interesting!

t.

-- 

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