From: Bertram Scharpf <lists@...>
Date: 2009-07-17T05:59:48+09:00
Subject: Re: case statement puzzle

Hi,

Am Freitag, 17. Jul 2009, 02:12:27 +0900 schrieb Tom Cloyd:
> James Coglan wrote:
>> 2009/7/16 Tom Cloyd <tomcloyd@comcast.net>
>>>
>>> x='1'
>>> case
>>> when x =='0'
>>>  puts '0'
>>> when (1..5).include? x.to_i
>>>  puts '1'
>>> end
>>
>> What about:
>>
>> x='1'
>> case
>> when x =='0'
>>  puts '0'
>> when '1'..'5'
>>  puts '1'
>> end
>>
> THANKS! That's the "missing piece" - I need to study up on "===", about 
> which I know nothing.

This will output "1" because the Range object '1'..'5' is not nil
and not false. It has nothing to do with the === operator. You
could also write

  x='1'
  case
    when x == '0'
      puts '0'
    when "hi, there"
      puts '1'
  end

To apply the === operator you have to mention the variable
after the "case" keyword.

  x = '1'
  case x
    when '0'      then puts '0'
    when '1'..'5' then puts '1'
  end

Bertram


-- 
Bertram Scharpf
Stuttgart, Deutschland/Germany
http://www.bertram-scharpf.de