From: "Matthew K. Williams" <matt@...>
Date: 2009-07-17T02:31:10+09:00
Subject: Re: case statement puzzle - correction

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On Fri, 17 Jul 2009, F. Senault wrote:

> Le 16 juillet 2009 =E0 18:58, Tom Cloyd a =E9crit :
>
>> x=3D'1'
>> case
>> when x =3D=3D'0'
>>   puts '0'
>> when (1..5).include? x.to_i
>>   puts '1'
>> end
>
> When in doubt, parenthesise :
>
>>> case
> ?>     when x =3D=3D '0'
>>>       puts '0'
>>>     when (1..5).include?(x.to_i)
>>>       puts '1'
>>>     end
> 1
> =3D> nil
>

Seconded.  You could also have said:

when ((1..5).include? x.to_i)


In ruby, parenthesis are optional.... except when they aren't. ;-)

Matt
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