From: Tom Cloyd <tomcloyd@...>
Date: 2009-07-17T02:12:27+09:00
Subject: Re: case statement puzzle

James Coglan wrote:
> 2009/7/16 Tom Cloyd <tomcloyd@comcast.net>
>
>   
>> I'm missing something here, and cannot see the problem:
>>
>> x='1'
>> (1..5).include? x.to_i  # => true
>>
>> But...
>>
>> x='1'
>> case
>> when x =='0'
>>  puts '0'
>> when (1..5).include? x.to_i
>>  puts '1'
>> end
>>     
>
>
> What about:
>
> x='1'
> case
> when x =='0'
>  puts '0'
> when '1'..'5'
>  puts '1'
> end
>
> The basic idea is that anything following 'when' should respond to '===' to
> indicate membership, or type/pattern-matching. e.g. Module#=== tells you
> whether the argument is an instance of the receiving module, Regexp#===
> tests a regex against a string.
>
> --
> James Coglan
> http://jcoglan.com
>
>   
THANKS! That's the "missing piece" - I need to study up on "===", about 
which I know nothing.

t.

-- 

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Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
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