From: James Coglan <jcoglan@...>
Date: 2009-07-17T01:55:46+09:00
Subject: Re: case statement puzzle

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2009/7/16 Tom Cloyd <tomcloyd@comcast.net>

> I'm missing something here, and cannot see the problem:
>
> x='1'
> (1..5).include? x.to_i  # => true
>
> But...
>
> x='1'
> case
> when x =='0'
>  puts '0'
> when (1..5).include? x.to_i
>  puts '1'
> end


What about:

x='1'
case
when x =='0'
 puts '0'
when '1'..'5'
 puts '1'
end

The basic idea is that anything following 'when' should respond to '===' to
indicate membership, or type/pattern-matching. e.g. Module#=== tells you
whether the argument is an instance of the receiving module, Regexp#===
tests a regex against a string.

--
James Coglan
http://jcoglan.com

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